7. Heat

Overview

Slides

Skills and Understanding

Equations

\[ \begin{array}{cc} Q = m c \Delta t \quad \quad \quad Q = mh \quad \quad \quad Q_{A} = -Q_{B} \\ \end{array} \]

Vocabulary

7.1 Introduction to Heat

Temperature is a scale for measuring the average kinetic energy of a group of molecules. There are multiple scales for temperature including Celsius, Fahrenheit, and Kelvin.

A thermal conductor is a mterial which quickly transfers heat throughout itself. Most metals are thermal conductors. A thermal insulator is a material which does not transfer heat well. Examples include wood and air.

7.2 Heat Transfer

Heat transfer describes the movement of heat energy.

Conduction is heat transfer through contact. Kinetic energy is transferred rom one molecule to another through collisions.

Convection is heat transfer through currents. Due to thermal expansion, hotter fluids (liquids or gases) are less dense so they rise. Cooler fluids sink, may heat up, and then continue the process of convection.

Radiation is heat transfer by electromagnetic waves. The Earth, for example, receives a tremendous amount of heat energy through the radiation emitted by the sun.

7.3 Specific Heat Capacity

Different substances change temperature at different rates. Specific heat is a property of matter and relates the change in temperature of a substance and the amount of heat energy it gains or loses. We will measure specific heat capacity in \(\frac{\text{J}}{\text{g}}^{\circ}\text{C}\).

Here is a table of some specific heat capacities:

MaterialSpecific Heat (J/g \(^\circ\)C)
Solid water2.10
Liquid water4.18
Water vapor2.01
Iron0.45
Aluminum0.90
Silver0.24
Copper0.39
Wood1.76
Vegetable oil2.00

The heat equation which uses specific heat is \[Q = mc \Delta T\] where \(Q\) is heat energy gained or lost, \(m\) is mass (in grams), \(c\) is the specific heat, and \(\Delta T\) is the change in temperature.

A pot of water is placed onto a stove. 44,000 J of heat energy is added to it, raising the temperature by 7.8\(^{\circ}C\). What is the mass of the water?
We are given: \[Q = 44000\] \[ \Delta T = 7.8\] and since we know the pot contains water, \[c = 4.18\] Using the heat equation \[ Q = m c \Delta T \] we can solve for m: \[ m = \frac{Q}{c \Delta T} \] and substitute to get \[ m = \frac{Q}{c \Delta T} = \frac{44000}{4.18 \cdot 7.8} = 1350 \text{ g} \]

7.4 Calorimetry